(x+1)+(x+1)+(2x+3)+(2x+3)=38

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Solution for (x+1)+(x+1)+(2x+3)+(2x+3)=38 equation: 



(x+1)+(x+1)+(2x+3)+(2x+3)=38

We move all terms to the left:

(x+1)+(x+1)+(2x+3)+(2x+3)-(38)=0

We get rid of parentheses

x+x+2x+2x+1+1+3+3-38=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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