(x+1)(x-4)-2=(x+2)(x-3)-x

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Solution for (x+1)(x-4)-2=(x+2)(x-3)-x equation: 



(x+1)(x-4)-2=(x+2)(x-3)-x

We move all terms to the left:

(x+1)(x-4)-2-((x+2)(x-3)-x)=0

We multiply parentheses ..

(+x^2-4x+x-4)-((x+2)(x-3)-x)-2=0



We calculate terms in parentheses: -((x+2)(x-3)-x), so:

(x+2)(x-3)-x

We add all the numbers together, and all the variables

-1x+(x+2)(x-3)

We multiply parentheses ..

(+x^2-3x+2x-6)-1x

We get rid of parentheses

x^2-3x+2x-1x-6

We add all the numbers together, and all the variables

x^2-2x-6

Back to the equation:

-(x^2-2x-6)



We get rid of parentheses

x^2-x^2-4x+x+2x-4+6-2=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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