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(x+1)(x-2)=180
We move all terms to the left:
(x+1)(x-2)-(180)=0
We multiply parentheses ..
(+x^2-2x+x-2)-180=0
We get rid of parentheses
x^2-2x+x-2-180=0
We add all the numbers together, and all the variables
x^2-1x-182=0
a = 1; b = -1; c = -182;
Δ = b2-4ac
Δ = -12-4·1·(-182)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-27}{2*1}=\frac{-26}{2} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+27}{2*1}=\frac{28}{2} =14 $
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