(x+1)(x-12)=0

Solution for (x+1)(x-12)=0 equation:

Simplifying
(x + 1)(x + -12) = 0

Reorder the terms:
(1 + x)(x + -12) = 0

Reorder the terms:
(1 + x)(-12 + x) = 0

Multiply (1 + x) * (-12 + x)
(1(-12 + x) + x(-12 + x)) = 0
((-12 * 1 + x * 1) + x(-12 + x)) = 0
((-12 + 1x) + x(-12 + x)) = 0
(-12 + 1x + (-12 * x + x * x)) = 0
(-12 + 1x + (-12x + x2)) = 0

Combine like terms: 1x + -12x = -11x
(-12 + -11x + x2) = 0

Solving
-12 + -11x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -1x)(12 + -1x) = 0

Subproblem 1
Set the factor '(-1 + -1x)' equal to zero and attempt to solve:

Simplifying
-1 + -1x = 0

Solving
-1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1x = 0 + 1
-1x = 0 + 1

Combine like terms: 0 + 1 = 1
-1x = 1

Divide each side by '-1'.
x = -1

Simplifying
x = -1
Subproblem 2
Set the factor '(12 + -1x)' equal to zero and attempt to solve:

Simplifying
12 + -1x = 0

Solving
12 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1x = 0 + -12
-1x = 0 + -12

Combine like terms: 0 + -12 = -12
-1x = -12

Divide each side by '-1'.
x = 12

Simplifying
x = 12
Solution
x = {-1, 12}