(x+1)(x-1)-4=0

Solution for (x+1)(x-1)-4=0 equation:

Simplifying
(x + 1)(x + -1) + -4 = 0

Reorder the terms:
(1 + x)(x + -1) + -4 = 0

Reorder the terms:
(1 + x)(-1 + x) + -4 = 0

Multiply (1 + x) * (-1 + x)
(1(-1 + x) + x(-1 + x)) + -4 = 0
((-1 * 1 + x * 1) + x(-1 + x)) + -4 = 0
((-1 + 1x) + x(-1 + x)) + -4 = 0
(-1 + 1x + (-1 * x + x * x)) + -4 = 0
(-1 + 1x + (-1x + x2)) + -4 = 0

Combine like terms: 1x + -1x = 0
(-1 + 0 + x2) + -4 = 0
(-1 + x2) + -4 = 0

Reorder the terms:
-1 + -4 + x2 = 0

Combine like terms: -1 + -4 = -5
-5 + x2 = 0

Solving
-5 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + x2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + x2 = 0 + 5
x2 = 0 + 5

Combine like terms: 0 + 5 = 5
x2 = 5

Simplifying
x2 = 5

Take the square root of each side:
x = {-2.236067978, 2.236067978}