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(x+1)(x+4)=x2+5x+4
We move all terms to the left:
(x+1)(x+4)-(x2+5x+4)=0
We add all the numbers together, and all the variables
-(+x^2+5x+4)+(x+1)(x+4)=0
We get rid of parentheses
-x^2-5x+(x+1)(x+4)-4=0
We multiply parentheses ..
-x^2+(+x^2+4x+x+4)-5x-4=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+4x+x+4)-5x-4=0
We get rid of parentheses
-1x^2+x^2+4x+x-5x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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