(x+1)(x+2)=2

Solution for (x+1)(x+2)=2 equation:

Simplifying
(x + 1)(x + 2) = 2

Reorder the terms:
(1 + x)(x + 2) = 2

Reorder the terms:
(1 + x)(2 + x) = 2

Multiply (1 + x) * (2 + x)
(1(2 + x) + x(2 + x)) = 2
((2 * 1 + x * 1) + x(2 + x)) = 2
((2 + 1x) + x(2 + x)) = 2
(2 + 1x + (2 * x + x * x)) = 2
(2 + 1x + (2x + x2)) = 2

Combine like terms: 1x + 2x = 3x
(2 + 3x + x2) = 2

Add '-2' to each side of the equation.
2 + 3x + -2 + x2 = 2 + -2

Reorder the terms:
2 + -2 + 3x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
0 + 3x + x2 = 2 + -2
3x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
3x + x2 = 0

Solving
3x + x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(3 + x) = 0

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0
Subproblem 2
Set the factor '(3 + x)' equal to zero and attempt to solve:

Simplifying
3 + x = 0

Solving
3 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + x = 0 + -3
x = 0 + -3

Combine like terms: 0 + -3 = -3
x = -3

Simplifying
x = -3
Solution
x = {0, -3}