(x+1)(x+2)=(x-3)(x-4)

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Solution for (x+1)(x+2)=(x-3)(x-4) equation: 



(x+1)(x+2)=(x-3)(x-4)

We move all terms to the left:

(x+1)(x+2)-((x-3)(x-4))=0

We multiply parentheses ..

(+x^2+2x+x+2)-((x-3)(x-4))=0



We calculate terms in parentheses: -((x-3)(x-4)), so:

(x-3)(x-4)

We multiply parentheses ..

(+x^2-4x-3x+12)

We get rid of parentheses

x^2-4x-3x+12

We add all the numbers together, and all the variables

x^2-7x+12

Back to the equation:

-(x^2-7x+12)



We get rid of parentheses

x^2-x^2+2x+x+7x+2-12=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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