(x+1)(x+2)+4x-10=x2+10x-1

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Solution for (x+1)(x+2)+4x-10=x2+10x-1 equation: 



(x+1)(x+2)+4x-10=x2+10x-1

We move all terms to the left:

(x+1)(x+2)+4x-10-(x2+10x-1)=0

We add all the numbers together, and all the variables

-(+x^2+10x-1)+(x+1)(x+2)+4x-10=0

We add all the numbers together, and all the variables

-(+x^2+10x-1)+4x+(x+1)(x+2)-10=0

We get rid of parentheses

-x^2-10x+4x+(x+1)(x+2)+1-10=0

We multiply parentheses ..

-x^2+(+x^2+2x+x+2)-10x+4x+1-10=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+2x+x+2)-6x-9=0

We get rid of parentheses

-1x^2+x^2+2x+x-6x+2-9=0

We add all the numbers together, and all the variables

-3x-7=0

We move all terms containing x to the left, all other terms to the right

-3x=7

x=7/-3

x=-2+1/3

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