(x+1)(x+1)=12+(x-5)(x-5)

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Solution for (x+1)(x+1)=12+(x-5)(x-5) equation: 



(x+1)(x+1)=12+(x-5)(x-5)

We move all terms to the left:

(x+1)(x+1)-(12+(x-5)(x-5))=0

We multiply parentheses ..

(+x^2+x+x+1)-(12+(x-5)(x-5))=0



We calculate terms in parentheses: -(12+(x-5)(x-5)), so:

12+(x-5)(x-5)

determiningTheFunctionDomain
(x-5)(x-5)+12

We multiply parentheses ..

(+x^2-5x-5x+25)+12

We get rid of parentheses

x^2-5x-5x+25+12

We add all the numbers together, and all the variables

x^2-10x+37

Back to the equation:

-(x^2-10x+37)



We get rid of parentheses

x^2-x^2+x+x+10x+1-37=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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