(x+1)(2x+1)=(x+3)(2x+3)+-14

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Solution for (x+1)(2x+1)=(x+3)(2x+3)+-14 equation: 



(x+1)(2x+1)=(x+3)(2x+3)+-14

We move all terms to the left:

(x+1)(2x+1)-((x+3)(2x+3)+-14)=0

We use the square of the difference formula

(x+1)(2x+1)-((x+3)(2x+3)-14)=0

We multiply parentheses ..

(+2x^2+x+2x+1)-((x+3)(2x+3)-14)=0



We calculate terms in parentheses: -((x+3)(2x+3)-14), so:

(x+3)(2x+3)-14

We multiply parentheses ..

(+2x^2+3x+6x+9)-14

We get rid of parentheses

2x^2+3x+6x+9-14

We add all the numbers together, and all the variables

2x^2+9x-5

Back to the equation:

-(2x^2+9x-5)



We get rid of parentheses

2x^2-2x^2+x+2x-9x+1+5=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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