(x+)2=x2+10x+

Solution for (x+)2=x2+10x+ equation:

(x+)2=x2+10x+

We move all terms to the left:

(x+)2-(x2+10x+)=0

We add all the numbers together, and all the variables

-(+x^2+10x+)+(+x)2=0

We multiply parentheses

-(+x^2+10x+)+2x=0

We get rid of parentheses

-x^2-10x+2x-=0

We add all the numbers together, and all the variables

-1x^2-8x=0

a = -1; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·(-1)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*-1}=\frac{0}{-2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*-1}=\frac{16}{-2}
=-8
$