(x+)(8x+1)=18x

Solution for (x+)(8x+1)=18x equation:

(x+)(8x+1)=18x

We move all terms to the left:

(x+)(8x+1)-(18x)=0

We add all the numbers together, and all the variables

(+x)(8x+1)-18x=0

We add all the numbers together, and all the variables

-18x+(+x)(8x+1)=0

We multiply parentheses ..

(+8x^2+x)-18x=0

We get rid of parentheses

8x^2+x-18x=0

We add all the numbers together, and all the variables

8x^2-17x=0

a = 8; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·8·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*8}=\frac{34}{16}
=2+1/8
$