(x*2+5)(3+x*4)(100x*2-10)(100x*2+10)=0

Solution for (x*2+5)(3+x*4)(100x*2-10)(100x*2+10)=0 equation:

(x*2+5)(3+x*4)(100x*2-10)(100x*2+10)=0

We add all the numbers together, and all the variables

(x*2+5)(x*4+3)(100x*2-10)(100x*2+10)=0

We multiply parentheses ..

(+8x^2+6x+20x+15)(100x*2-10)(100x*2+10)=0

We use the square of the difference formula

40000x^2-100=0

a = 40000; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·40000·(-100)
Δ = 16000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16000000}=4000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4000}{2*40000}=\frac{-4000}{80000}
=-1/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4000}{2*40000}=\frac{4000}{80000}
=1/20
$