(x*2+2x-5)-(3x+2)=x*2-1

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Solution for (x*2+2x-5)-(3x+2)=x*2-1 equation: 



(x*2+2x-5)-(3x+2)=x*2-1

We move all terms to the left:

(x*2+2x-5)-(3x+2)-(x*2-1)=0

We add all the numbers together, and all the variables

(2x+x*2-5)-(3x+2)-(x*2-1)=0

We get rid of parentheses

2x+x*2-3x-x*2-5-2+1=0

We add all the numbers together, and all the variables

-1x+x*2-x*2-6=0

Wy multiply elements

-1x+2x-2x-6=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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