(x*((30x)+53))+5=0

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Solution for (x*((30x)+53))+5=0 equation:



(x((30x)+53))+5=0
We calculate terms in parentheses: +(x(30x+53)), so:
x(30x+53)
We multiply parentheses
30x^2+53x
Back to the equation:
+(30x^2+53x)
We get rid of parentheses
30x^2+53x+5=0
a = 30; b = 53; c = +5;
Δ = b2-4ac
Δ = 532-4·30·5
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-47}{2*30}=\frac{-100}{60} =-1+2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+47}{2*30}=\frac{-6}{60} =-1/10 $

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