(x)=x2+4

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Solution for (x)=x2+4 equation: 



(x)=x2+4

We move all terms to the left:

(x)-(x2+4)=0

We add all the numbers together, and all the variables

-(+x^2+4)+x=0

We get rid of parentheses

-x^2+x-4=0

We add all the numbers together, and all the variables

-1x^2+x-4=0

a = -1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-1)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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