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(x)=3x^2+6x+3
We move all terms to the left:
(x)-(3x^2+6x+3)=0
We get rid of parentheses
-3x^2+x-6x-3=0
We add all the numbers together, and all the variables
-3x^2-5x-3=0
a = -3; b = -5; c = -3;
Δ = b2-4ac
Δ = -52-4·(-3)·(-3)
Δ = -11
Delta is less than zero, so there is no solution for the equation
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