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(x)=2x^2-6x+4
We move all terms to the left:
(x)-(2x^2-6x+4)=0
We get rid of parentheses
-2x^2+x+6x-4=0
We add all the numbers together, and all the variables
-2x^2+7x-4=0
a = -2; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·(-2)·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{17}}{2*-2}=\frac{-7-\sqrt{17}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{17}}{2*-2}=\frac{-7+\sqrt{17}}{-4} $
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