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(x)=-x2+400x-7500
We move all terms to the left:
(x)-(-x2+400x-7500)=0
We add all the numbers together, and all the variables
-(-1x^2+400x-7500)+x=0
We get rid of parentheses
1x^2-400x+x+7500=0
We add all the numbers together, and all the variables
x^2-399x+7500=0
a = 1; b = -399; c = +7500;
Δ = b2-4ac
Δ = -3992-4·1·7500
Δ = 129201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-399)-\sqrt{129201}}{2*1}=\frac{399-\sqrt{129201}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-399)+\sqrt{129201}}{2*1}=\frac{399+\sqrt{129201}}{2} $
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