(x)=-8x2+2x+18.

Solution for (x)=-8x2+2x+18. equation:

(x)=-8x^2+2x+18.

We move all terms to the left:

(x)-(-8x^2+2x+18.)=0

We get rid of parentheses

8x^2-2x+x-18.=0

We add all the numbers together, and all the variables

8x^2-1x-18=0

a = 8; b = -1; c = -18;
Δ = b2-4ac
Δ = -12-4·8·(-18)
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{577}}{2*8}=\frac{1-\sqrt{577}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{577}}{2*8}=\frac{1+\sqrt{577}}{16}
$