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(x)=-2x^2+12x+54
We move all terms to the left:
(x)-(-2x^2+12x+54)=0
We get rid of parentheses
2x^2-12x+x-54=0
We add all the numbers together, and all the variables
2x^2-11x-54=0
a = 2; b = -11; c = -54;
Δ = b2-4ac
Δ = -112-4·2·(-54)
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{553}}{2*2}=\frac{11-\sqrt{553}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{553}}{2*2}=\frac{11+\sqrt{553}}{4} $
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