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(x)=-10x^2+500x+7615
We move all terms to the left:
(x)-(-10x^2+500x+7615)=0
We get rid of parentheses
10x^2-500x+x-7615=0
We add all the numbers together, and all the variables
10x^2-499x-7615=0
a = 10; b = -499; c = -7615;
Δ = b2-4ac
Δ = -4992-4·10·(-7615)
Δ = 553601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-499)-\sqrt{553601}}{2*10}=\frac{499-\sqrt{553601}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-499)+\sqrt{553601}}{2*10}=\frac{499+\sqrt{553601}}{20} $
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