(x)/(5x-25)-9=(1)/(x-5)

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Solution for (x)/(5x-25)-9=(1)/(x-5) equation:


D( x )

x-5 = 0

5*x-25 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

5*x-25 = 0

5*x-25 = 0

5*x-25 = 0 // + 25

5*x = 25 // : 5

x = 25/5

x = 5

x in (-oo:5) U (5:+oo)

x/(5*x-25)-9 = 1/(x-5) // - 1/(x-5)

x/(5*x-25)-(1/(x-5))-9 = 0

x/(5*x-25)-(x-5)^-1-9 = 0

x/(5*x-25)-1/(x-5)-9 = 0

(x*(x-5))/((5*x-25)*(x-5))+(-1*(5*x-25))/((5*x-25)*(x-5))+(-9*(5*x-25)*(x-5))/((5*x-25)*(x-5)) = 0

x*(x-5)-1*(5*x-25)-9*(5*x-25)*(x-5) = 0

x^2-45*x^2-10*x+450*x-1125+25 = 0

440*x-44*x^2-1100 = 0

440*x-44*x^2-1100 = 0

44*(10*x-x^2-25) = 0

10*x-x^2-25 = 0

DELTA = 10^2-(-25*(-1)*4)

DELTA = 0

x = -10/(-1*2)

x = 5 or x = 5

44*(x-5)^2 = 0

(44*(x-5)^2)/((5*x-25)*(x-5)) = 0

(44*(x-5)^2)/((5*x-25)*(x-5)) = 0 // * (5*x-25)*(x-5)

44*(x-5)^2 = 0

x-5 = 0 // + 5

x = 5

x in { 5}

x belongs to the empty set

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