(x)/(2)=3+(x-30)/(5)

Solution for (x)/(2)=3+(x-30)/(5) equation:

(x)/(2)=3+(x-30)/(5)

We move all terms to the left:

(x)/(2)-(3+(x-30)/(5))=0

We calculate fractions


5x^2/()+(-(3+(x-30)*2)/()=0


We calculate terms in parentheses: +(-(3+(x-30)*2)/(), so:

-(3+(x-30)*2)/(

We multiply all the terms by the denominator


-(3+(x-30)*2)


We calculate terms in parentheses: -(3+(x-30)*2), so:

3+(x-30)*2

determiningTheFunctionDomain
(x-30)*2+3

We multiply parentheses

2x-60+3

We add all the numbers together, and all the variables

2x-57

Back to the equation:

-(2x-57)


We get rid of parentheses

-2x+57

Back to the equation:

+(-2x+57)


We get rid of parentheses

5x^2/()-2x+57=0

We multiply all the terms by the denominator


5x^2-2x*()+57*()=0

We add all the numbers together, and all the variables

5x^2-2x*()=0