(x)+(x+2)+(x+4)=57

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Solution for (x)+(x+2)+(x+4)=57 equation:


Simplifying
(x) + (x + 2) + (x + 4) = 57
x + (x + 2) + (x + 4) = 57

Reorder the terms:
x + (2 + x) + (x + 4) = 57

Remove parenthesis around (2 + x)
x + 2 + x + (x + 4) = 57

Reorder the terms:
x + 2 + x + (4 + x) = 57

Remove parenthesis around (4 + x)
x + 2 + x + 4 + x = 57

Reorder the terms:
2 + 4 + x + x + x = 57

Combine like terms: 2 + 4 = 6
6 + x + x + x = 57

Combine like terms: x + x = 2x
6 + 2x + x = 57

Combine like terms: 2x + x = 3x
6 + 3x = 57

Solving
6 + 3x = 57

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3x = 57 + -6

Combine like terms: 6 + -6 = 0
0 + 3x = 57 + -6
3x = 57 + -6

Combine like terms: 57 + -6 = 51
3x = 51

Divide each side by '3'.
x = 17

Simplifying
x = 17

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