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(x)+(x+1)+(x+2)+(x+3)=141
We move all terms to the left:
(x)+(x+1)+(x+2)+(x+3)-(141)=0
We get rid of parentheses
x+x+x+x+1+2+3-141=0
We add all the numbers together, and all the variables
4x-135=0
We move all terms containing x to the left, all other terms to the right
4x=135
x=135/4
x=33+3/4
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