(x)+(6x-2)+(3x)=180

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Solution for (x)+(6x-2)+(3x)=180 equation: 



(x)+(6x-2)+(3x)=180

We move all terms to the left:

(x)+(6x-2)+(3x)-(180)=0

We add all the numbers together, and all the variables

4x+(6x-2)-180=0

We get rid of parentheses

4x+6x-2-180=0

We add all the numbers together, and all the variables

10x-182=0

We move all terms containing x to the left, all other terms to the right

10x=182

x=182/10

x=18+1/5

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