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(x)(x)(x-3)=14000
We move all terms to the left:
(x)(x)(x-3)-(14000)=0
We multiply parentheses
x^2-3x-14000=0
a = 1; b = -3; c = -14000;
Δ = b2-4ac
Δ = -32-4·1·(-14000)
Δ = 56009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{56009}}{2*1}=\frac{3-\sqrt{56009}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{56009}}{2*1}=\frac{3+\sqrt{56009}}{2} $
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