(x)(x+2)=59+2(x+x+2)

Solution for (x)(x+2)=59+2(x+x+2) equation:

(x)(x+2)=59+2(x+x+2)

We move all terms to the left:

(x)(x+2)-(59+2(x+x+2))=0

We add all the numbers together, and all the variables

x(x+2)-(59+2(2x+2))=0

We multiply parentheses

x^2+2x-(59+2(2x+2))=0


We calculate terms in parentheses: -(59+2(2x+2)), so:

59+2(2x+2)

determiningTheFunctionDomain
2(2x+2)+59

We multiply parentheses

4x+4+59

We add all the numbers together, and all the variables

4x+63

Back to the equation:

-(4x+63)


We get rid of parentheses

x^2+2x-4x-63=0

We add all the numbers together, and all the variables

x^2-2x-63=0

a = 1; b = -2; c = -63;
Δ = b2-4ac
Δ = -22-4·1·(-63)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-16}{2*1}=\frac{-14}{2}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+16}{2*1}=\frac{18}{2}
=9
$