(x)(x+2)=288

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Solution for (x)(x+2)=288 equation:


Simplifying
(x)(x + 2) = 288

Reorder the terms:
x(2 + x) = 288
(2 * x + x * x) = 288
(2x + x2) = 288

Solving
2x + x2 = 288

Solving for variable 'x'.

Reorder the terms:
-288 + 2x + x2 = 288 + -288

Combine like terms: 288 + -288 = 0
-288 + 2x + x2 = 0

Factor a trinomial.
(-18 + -1x)(16 + -1x) = 0

Subproblem 1

Set the factor '(-18 + -1x)' equal to zero and attempt to solve: Simplifying -18 + -1x = 0 Solving -18 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '18' to each side of the equation. -18 + 18 + -1x = 0 + 18 Combine like terms: -18 + 18 = 0 0 + -1x = 0 + 18 -1x = 0 + 18 Combine like terms: 0 + 18 = 18 -1x = 18 Divide each side by '-1'. x = -18 Simplifying x = -18

Subproblem 2

Set the factor '(16 + -1x)' equal to zero and attempt to solve: Simplifying 16 + -1x = 0 Solving 16 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + -1x = 0 + -16 Combine like terms: 16 + -16 = 0 0 + -1x = 0 + -16 -1x = 0 + -16 Combine like terms: 0 + -16 = -16 -1x = -16 Divide each side by '-1'. x = 16 Simplifying x = 16

Solution

x = {-18, 16}

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