(x)(x+12)=(x+12)(x+5)

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Solution for (x)(x+12)=(x+12)(x+5) equation: 



(x)(x+12)=(x+12)(x+5)

We move all terms to the left:

(x)(x+12)-((x+12)(x+5))=0

We multiply parentheses

x^2+12x-((x+12)(x+5))=0

We multiply parentheses ..

x^2-((+x^2+5x+12x+60))+12x=0



We calculate terms in parentheses: -((+x^2+5x+12x+60)), so:

(+x^2+5x+12x+60)

We get rid of parentheses

x^2+5x+12x+60

We add all the numbers together, and all the variables

x^2+17x+60

Back to the equation:

-(x^2+17x+60)



We add all the numbers together, and all the variables

x^2+12x-(x^2+17x+60)=0

We get rid of parentheses

x^2-x^2+12x-17x-60=0

We add all the numbers together, and all the variables

-5x-60=0

We move all terms containing x to the left, all other terms to the right

-5x=60

x=60/-5

x=-12

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