(x)(X+1)+3=96

Solution for (x)(X+1)+3=96 equation:

(x)(x+1)+3=96

We move all terms to the left:

(x)(x+1)+3-(96)=0

We add all the numbers together, and all the variables

x(x+1)-93=0

We multiply parentheses

x^2+x-93=0

a = 1; b = 1; c = -93;
Δ = b2-4ac
Δ = 12-4·1·(-93)
Δ = 373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{373}}{2*1}=\frac{-1-\sqrt{373}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{373}}{2*1}=\frac{-1+\sqrt{373}}{2}
$