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(x(x-2))/2=2.5
We move all terms to the left:
(x(x-2))/2-(2.5)=0
We add all the numbers together, and all the variables
(x(x-2))/2-2.5=0
We multiply all the terms by the denominator
(x(x-2))-(2.5)*2=0
We calculate terms in parentheses: +(x(x-2)), so:We add all the numbers together, and all the variables
x(x-2)
We multiply parentheses
x^2-2x
Back to the equation:
+(x^2-2x)
(x^2-2x)-5=0
We get rid of parentheses
x^2-2x-5=0
a = 1; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·1·(-5)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{6}}{2*1}=\frac{2-2\sqrt{6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{6}}{2*1}=\frac{2+2\sqrt{6}}{2} $
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