(x^2+6x)^2+13(x^2+6x)=-40

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Solution for (x^2+6x)^2+13(x^2+6x)=-40 equation: 



(x^2+6x)^2+13(x^2+6x)=-40

We move all terms to the left:

(x^2+6x)^2+13(x^2+6x)-(-40)=0

We add all the numbers together, and all the variables

(x^2+6x)^2+13(x^2+6x)+40=0

We multiply parentheses

13x^2+(x^2+6x)^2+78x+40=0

We add all the numbers together, and all the variables

13x^2+78x+(x^2+6x)^2+40=0

We move all terms containing x to the left, all other terms to the right

13x^2+78x+(x^2+6x)^2=-40

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