(w-6)/5=(2w+3)/2

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Solution for (w-6)/5=(2w+3)/2 equation: 



(w-6)/5=(2w+3)/2

We move all terms to the left:

(w-6)/5-((2w+3)/2)=0

We calculate fractions


w/()+(-((2w+3)*5)/()=0



We calculate terms in parentheses: +(-((2w+3)*5)/(), so:

-((2w+3)*5)/(

We multiply all the terms by the denominator


-((2w+3)*5)



We calculate terms in parentheses: -((2w+3)*5), so:

(2w+3)*5

We multiply parentheses

10w+15

Back to the equation:

-(10w+15)



We get rid of parentheses

-10w-15

Back to the equation:

+(-10w-15)



We get rid of parentheses

w/()-10w-15=0

We multiply all the terms by the denominator


w-10w*()-15*()=0

We add all the numbers together, and all the variables

w-10w*()=0

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