(w-1/w+2)+1=(w-7/w-6)

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Solution for (w-1/w+2)+1=(w-7/w-6) equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w-(1/w)+1+2 = w-(7/w)-6 // - w-(7/w)-6

w-w-(1/w)+7/w+1+2+6 = 0

w-w-w^-1+7/w+1+2+6 = 0

6*w^-1 = -9 // : 6

w^-1 = -3/2

-1 < 0

1/(w^1) = -3/2 // * w^1

1 = -3/2*w^1 // : -3/2

-2/3 = w^1

w = -2/3

w = -2/3

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