(w+7)(w-12)=0

Solution for (w+7)(w-12)=0 equation:

(w+7)(w-12)=0

We multiply parentheses ..

(+w^2-12w+7w-84)=0

We get rid of parentheses

w^2-12w+7w-84=0

We add all the numbers together, and all the variables

w^2-5w-84=0

a = 1; b = -5; c = -84;
Δ = b2-4ac
Δ = -52-4·1·(-84)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-19}{2*1}=\frac{-14}{2}
=-7
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+19}{2*1}=\frac{24}{2}
=12
$