(w+60)w=1800

Solution for (w+60)w=1800 equation:

(w+60)w=1800

We move all terms to the left:

(w+60)w-(1800)=0

We multiply parentheses

w^2+60w-1800=0

a = 1; b = 60; c = -1800;
Δ = b2-4ac
Δ = 602-4·1·(-1800)
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{3}}{2*1}=\frac{-60-60\sqrt{3}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{3}}{2*1}=\frac{-60+60\sqrt{3}}{2}
$