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(w+5)w=76
We move all terms to the left:
(w+5)w-(76)=0
We multiply parentheses
w^2+5w-76=0
a = 1; b = 5; c = -76;
Δ = b2-4ac
Δ = 52-4·1·(-76)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{329}}{2*1}=\frac{-5-\sqrt{329}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{329}}{2*1}=\frac{-5+\sqrt{329}}{2} $
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