(w+5)(w+11)=0

Solution for (w+5)(w+11)=0 equation:

(w+5)(w+11)=0

We multiply parentheses ..

(+w^2+11w+5w+55)=0

We get rid of parentheses

w^2+11w+5w+55=0

We add all the numbers together, and all the variables

w^2+16w+55=0

a = 1; b = 16; c = +55;
Δ = b2-4ac
Δ = 162-4·1·55
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-6}{2*1}=\frac{-22}{2}
=-11
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+6}{2*1}=\frac{-10}{2}
=-5
$