(w+40)+(w+40)+w+w=(w+45)+(w+45)+(w+45)

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Solution for (w+40)+(w+40)+w+w=(w+45)+(w+45)+(w+45) equation: 



(w+40)+(w+40)+w+w=(w+45)+(w+45)+(w+45)

We move all terms to the left:

(w+40)+(w+40)+w+w-((w+45)+(w+45)+(w+45))=0

We add all the numbers together, and all the variables

2w+(w+40)+(w+40)-((w+45)+(w+45)+(w+45))=0

We get rid of parentheses

2w+w+w-((w+45)+(w+45)+(w+45))+40+40=0



We calculate terms in parentheses: -((w+45)+(w+45)+(w+45)), so:

(w+45)+(w+45)+(w+45)

We get rid of parentheses

w+w+w+45+45+45

We add all the numbers together, and all the variables

3w+135

Back to the equation:

-(3w+135)



We add all the numbers together, and all the variables

4w-(3w+135)+80=0

We get rid of parentheses

4w-3w-135+80=0

We add all the numbers together, and all the variables

w-55=0

We move all terms containing w to the left, all other terms to the right

w=55

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