(w+22)(w-10)=0

Solution for (w+22)(w-10)=0 equation:

(w+22)(w-10)=0

We multiply parentheses ..

(+w^2-10w+22w-220)=0

We get rid of parentheses

w^2-10w+22w-220=0

We add all the numbers together, and all the variables

w^2+12w-220=0

a = 1; b = 12; c = -220;
Δ = b2-4ac
Δ = 122-4·1·(-220)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-32}{2*1}=\frac{-44}{2}
=-22
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+32}{2*1}=\frac{20}{2}
=10
$