(v-5)/6+v/6=(v+4)/9-1

Solution for (v-5)/6+v/6=(v+4)/9-1 equation:

(v-5)/6+v/6=(v+4)/9-1

We move all terms to the left:

(v-5)/6+v/6-((v+4)/9-1)=0

We calculate fractions


(10v-5)/()+(-((v+4)*6)/()=0


We calculate terms in parentheses: +(-((v+4)*6)/(), so:

-((v+4)*6)/(

We multiply all the terms by the denominator


-((v+4)*6)


We calculate terms in parentheses: -((v+4)*6), so:

(v+4)*6

We multiply parentheses

6v+24

Back to the equation:

-(6v+24)


We get rid of parentheses

-6v-24

Back to the equation:

+(-6v-24)


We get rid of parentheses

(10v-5)/()-6v-24=0

We multiply all the terms by the denominator


(10v-5)-6v*()-24*()=0

We add all the numbers together, and all the variables

(10v-5)-6v*()=0

We get rid of parentheses

10v-6v*()-5=0

We move all terms containing v to the left, all other terms to the right

10v-6v*()=5