(v+5)(v+5)=0

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Solution for (v+5)(v+5)=0 equation: 



(v+5)(v+5)=0

We multiply parentheses ..

(+v^2+5v+5v+25)=0

We get rid of parentheses

v^2+5v+5v+25=0

We add all the numbers together, and all the variables

v^2+10v+25=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-10}{2}=-5$

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