(v+2)+2v=3(v-1)+9

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Solution for (v+2)+2v=3(v-1)+9 equation: 



(v+2)+2v=3(v-1)+9

We move all terms to the left:

(v+2)+2v-(3(v-1)+9)=0

We add all the numbers together, and all the variables

2v+(v+2)-(3(v-1)+9)=0

We get rid of parentheses

2v+v-(3(v-1)+9)+2=0



We calculate terms in parentheses: -(3(v-1)+9), so:

3(v-1)+9

We multiply parentheses

3v-3+9

We add all the numbers together, and all the variables

3v+6

Back to the equation:

-(3v+6)



We add all the numbers together, and all the variables

3v-(3v+6)+2=0

We get rid of parentheses

3v-3v-6+2=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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