(u/6)-(u/9)=(1/6)

Solution for (u/6)-(u/9)=(1/6) equation:

(u/6)-(u/9)=(1/6)

We move all terms to the left:

(u/6)-(u/9)-((1/6))=0

We add all the numbers together, and all the variables

(+u/6)-(+u/9)-((+1/6))=0

We get rid of parentheses

u/6-u/9-((+1/6))=0

We calculate fractions


(-216u^2)/()+9u/()+()/()=0

We add all the numbers together, and all the variables

(-216u^2)/()+9u/()+1=0

We multiply all the terms by the denominator


(-216u^2)+9u+1*()=0

We add all the numbers together, and all the variables

(-216u^2)+9u=0

We get rid of parentheses

-216u^2+9u=0

a = -216; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-216)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-216}=\frac{-18}{-432}
=1/24
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-216}=\frac{0}{-432}
=0
$