(u-3)/(u-5)=(u+2)/(u-7)+1

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Solution for (u-3)/(u-5)=(u+2)/(u-7)+1 equation:


D( u )

u-5 = 0

u-7 = 0

u-5 = 0

u-5 = 0

u-5 = 0 // + 5

u = 5

u-7 = 0

u-7 = 0

u-7 = 0 // + 7

u = 7

u in (-oo:5) U (5:7) U (7:+oo)

(u-3)/(u-5) = (u+2)/(u-7)+1 // - (u+2)/(u-7)+1

(u-3)/(u-5)-((u+2)/(u-7))-1 = 0

(u-3)/(u-5)+(-1*(u+2))/(u-7)-1 = 0

((u-3)*(u-7))/((u-5)*(u-7))+(-1*(u+2)*(u-5))/((u-5)*(u-7))+(-1*(u-5)*(u-7))/((u-5)*(u-7)) = 0

(u-3)*(u-7)-1*(u+2)*(u-5)-1*(u-5)*(u-7) = 0

12*u-u^2-7*u-35+31 = 0

5*u-u^2-4 = 0

5*u-u^2-4 = 0

5*u-u^2-4 = 0

DELTA = 5^2-(-4*(-1)*4)

DELTA = 9

DELTA > 0

u = (9^(1/2)-5)/(-1*2) or u = (-9^(1/2)-5)/(-1*2)

u = 1 or u = 4

(u-1)*(u-4) = 0

((u-1)*(u-4))/((u-5)*(u-7)) = 0

((u-1)*(u-4))/((u-5)*(u-7)) = 0 // * (u-5)*(u-7)

(u-1)*(u-4) = 0

( u-1 )

u-1 = 0 // + 1

u = 1

( u-4 )

u-4 = 0 // + 4

u = 4

u in { 1, 4 }

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