(u+5y+1)(2u-7y)=0

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Solution for (u+5y+1)(2u-7y)=0 equation:


Simplifying
(u + 5y + 1)(2u + -7y) = 0

Reorder the terms:
(1 + u + 5y)(2u + -7y) = 0

Multiply (1 + u + 5y) * (2u + -7y)
(1(2u + -7y) + u(2u + -7y) + 5y * (2u + -7y)) = 0
((2u * 1 + -7y * 1) + u(2u + -7y) + 5y * (2u + -7y)) = 0
((2u + -7y) + u(2u + -7y) + 5y * (2u + -7y)) = 0
(2u + -7y + (2u * u + -7y * u) + 5y * (2u + -7y)) = 0

Reorder the terms:
(2u + -7y + (-7uy + 2u2) + 5y * (2u + -7y)) = 0
(2u + -7y + (-7uy + 2u2) + 5y * (2u + -7y)) = 0
(2u + -7y + -7uy + 2u2 + (2u * 5y + -7y * 5y)) = 0
(2u + -7y + -7uy + 2u2 + (10uy + -35y2)) = 0

Reorder the terms:
(2u + -7uy + 10uy + 2u2 + -7y + -35y2) = 0

Combine like terms: -7uy + 10uy = 3uy
(2u + 3uy + 2u2 + -7y + -35y2) = 0

Solving
2u + 3uy + 2u2 + -7y + -35y2 = 0

Solving for variable 'u'.

The solution to this equation could not be determined.

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