(t-5)/3(t-5)/3=49

Solution for (t-5)/3(t-5)/3=49 equation:

t in (-oo:+oo)

(((t-5)/3)*(t-5))/3 = 49 // - 49

(((t-5)/3)*(t-5))/3-49 = 0

((t-5)^2)/(3^2)-49 = 0

((t-5)^2)/(3^2)+(-49*3^2)/(3^2) = 0

(t-5)^2-49*3^2 = 0

t^2-10*t-416 = 0

t^2-10*t-416 = 0

t^2-10*t-416 = 0

DELTA = (-10)^2-(-416*1*4)

DELTA = 1764

DELTA > 0

t = (1764^(1/2)+10)/(1*2) or t = (10-1764^(1/2))/(1*2)

t = 26 or t = -16

(t+16)*(t-26) = 0

((t+16)*(t-26))/(3^2) = 0

((t+16)*(t-26))/(3^2) = 0 // * 9

(t+16)*(t-26) = 0

( t+16 )

t+16 = 0 // - 16

t = -16

( t-26 )

t-26 = 0 // + 26

t = 26

t in { -16, 26 }